2.1
Determinants
by Cofactor Expansion; Cramer's Rule
Hwk: 1, 3ad, 4, 7, 16, 21, 22, 25, 29, T3
We will not define a determinant formally
until section 4. In the meantime, we'll
use working definitions that are equivalent to the formal definition.
a b c d
Def (for 2x2): If A = then det(A) =
ad – bc
Notation:
vertical bars around matrix instead of brackets
Minor of aij,
called Mij, is the determinant that results from
eliminating row i and col j
Cofactor if aij,
called Cij, is ±Mij, where
the sign can be calculated as (–1)i+j
It
is easiest to see the sign by picturing a checkerboard pattern of signs
(starting with + in upper left)
Cofactor expansion: det(A) = sum of aijCij
along any row or column (i.e.) sum of ± aijMij
Ex,
along row 1: a11M11
– a12M12 + a13M13 – ...
Ex,
down col 2: –a12M12
+ a22M22 – a32M32 + ...
Easiest calculation: Pick a row or column with the greatest number
of 0's -- this will reduce the number of determinants
you have to calculate.
Adjoint of a matrix:
adj(A)
is the transpose of a matrix whose entries are the cofactors of A
(the "matrix of cofactors"),
or in symbols, [Cij]T
Determinant formula for an inverse: A–1 = 1 / det(A) * adj(A)
Verify
special formula for inverse of a 2x2.
Thm 3: If
A is triangular [including diagonal], then det(A) = sum of entries on
main diagonal
Cramer's Rule for solving a system of
equations
I
recommend it for a small system where the coefficients are symbols (rather than
numbers).
Ex: use Cramer's rule to solve
for b and m
(equations for a least squares line
y = mx + b)
2.2 Evaluating Determinants by Row Reduction
Hwk 1a, 2, 3, 12, 14, 16 for #6, 14, 17 for #8, 18, 19
Thm: a. If A has a row or column of 0's, det(A)=0
Proof: cofactor expansion along row of 0's
by signed elementary products: every elementary product has a factor of 0
b. det(A)=det(AT)
Proof: cofactor expansion of A across 1st row = expansion of AT along 1st column
by signed elementary products: the signed elem. products are the same;
Thm: Determinant of a triangular matrix = product of entries on main diagonal
Proof: Repeated cofactor expansions across row 1
by signed elementary products: Every other elementary product must contain at least one 0
Thm: effect of elementary row operations
Row interchange: reverse sign
Proof by signed elementary products: reverse 2 factors in every elementary prod
Multiply a single row or column by a scalar k: multiply entire determinant by k
Proof by signed elementary products: multiply one entry in each elementary prod by k
Add a multiple of one row to another: no change Pr: omitted
Thm: Same results for multiplication on left by corresponding elementary matrices
[and, for that matter, for the elementary matrices themselves]
Thm: proportional rows or cols: det(A) = 0
Pr: Adding an appropriate multiple of the smaller row (or column) to the larger results in an all-zero row (or column)
Technique: Combination row (or column) reduction with cofactor expansion.
Aim: Make all but one entry in a row (or column) 0, then reduce dimension by cofactor expansion
2.3
Properties of
the Determinant Function
Hwk 1b, 2, 3, 4bd, 5abe, 6, 9, 12, 13, 14c, 15
(for 14c), 16, 18
1. det(kA) = kn det(A) Proof: all n rows are multiplied by k
2. det(A+B) ¹ det(A) + det(B) Counterexample in Ex 1; or let A = B = I2
3. Thm
1: but if A, B, C differ only in a
single row, and that row of C is sum of rows in A and B,
then det(A+B) = det(C) (Also
true for columns)
4. Thm 2: det(AB) = det(A)det(B) BIGGIE Proof requires several steps
a. Lemma: det(EB) = det(E)det(B) for an elementary matrix E
Proof: Thm 2.2.4 (multiplication by elementary matrix is same as elementary row operation)
Consequence: also valid for multiplication on the left by multiple elementary matrices
b. A is invertible iff ("if and only if") det(A)¹0 BIGGIE
Pr: Background: Let R = rref of A. Then R=Er...E2E1A
Since det(E)¹0, determinants of A and R are either both 0 or both nonzero.
(1) Assume A is invertible. R must = I, so det (R) and det (A) are nonzero.
(2) Assume det(A)¹0. Then det(R)¹0, so R cannot have a row of 0's.
(contrapositive of row of 0's implies det(A)=0)
Therefore, R = I (Thm 1.4.3: the rref of an n´n matrix either has a row of 0's or is In)
So A is invertible.
c. Consequence: A square matrix with two proportional rows/columns is not invertible
d. Proof that det(AB) = det(A)det(B):
(1) Case 1: A is not invertible. Then AB is not invertible (Th1.6.5 AB invertible implies A & B are invertible. Thus both det(AB) and det(A) equal 0
(2) Case 2: A is invertible. Write A as product of elementary matrices, multiply by B on right, take determinant.
5. det(A-1) = 1 / det(A) Pr: take determinent of A-1A = I
6. Systems of form Ax = λx Really homogeneous
(λI-A)x=0
det(λI-A)=0 iff system has nontrivial solutions "Characteristic equation" of A
λ = eigenvalue; the corresponding solutions are "eigenvectors"
7. More equivalent statements in "big theorem:" add det(A)¹0 as equiv to A is invertible
2.4 The Determinant Function: Combinatorial Approach
Hwk 1ab, 2ab, 5, 9, 13b, 17, 19, 22, 23a
Def: Permutation of the set of integers (1, 2, ..., n} is an arrangement, without omissions or repetitions
Ex: List some permutations of {1, 2, 3, 4, 5}
Counting note: number of permutations is n! (why?)
Def: an inversion occurs in a permutation whenever a larger integer precedes a smaller one
Ex: identify inversions in the prev example
How to count inversions: For each integer, count smaller integers to the right; add the results
Ex: prev
Def: A permutation is even or odd according to whether the number of inversions is even or odd
Ex: prev
Def: An elementary product from an n´n matrix A is a product of n factors from A, no two of which come from the same row or the same column
Arrange the factors of an elementary product in order by rows, and
Consider the permutation of the column numbers.
A signed elementary product is positive or negative according to whether the permutation of the columns is even (+) or odd (-)
Def: Let A be a square matrix. The determinant of A, det(A) = sum of the signed elementary products of A
The determinant is the single number result
Vertical bracket notation for the unevaluated determinant
Calculation of 2´2 det
Ex
Calculation of 3´3
Ex, with 6-arrow shortcut.
Caution: applies only to 3´3 (a 4´4 would need 4! = 24 diagonals, but only 8 exist)
How to write symbolically with summation symbol
Text
Return to: Merced College; Don Power Updated 02/12/07 by Don Power