MATH 4B -- LAB -- DERIVATIVES OF INVERSE FUNCTIONS NAME ________________
Example
1: Find the derivative of
. The derivative of
its inverse function x2 is known.
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Procedure: |
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Identify the goal: Find y¢ if ... |
y= |
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Solve for x |
x=y2 |
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Differentiate implicitly |
1=2y×y¢ |
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Solve for y¢ |
y¢=1/2y
and notice from earlier that y= |
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Write in terms of x |
Dx( |
Example 2: Find the derivative of ex. The derivative of its inverse ln(x) is Dx ln(x)=1/x.
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Procedure: |
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Identify the goal: Find y¢ if ... |
y=ex |
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Solve for x |
x=ln(y) |
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Differentiate implicitly |
1= y¢/y |
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Solve for y¢ |
y¢=y and notice from earlier that y=ex |
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Write in terms of x |
Dx(ex)=ex |
Example 3: Find the derivative of sin-1 x. The derivative of its inverse function sin(x) is known.
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Procedure: |
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Identify the goal: Find y¢ if ... |
y=sin-1 x |
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Solve for x |
x=sin(y) |
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Differentiate implicitly |
1=cos(y)×y¢ |
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Solve for y¢ |
y¢=1/cos(y) and notice from earlier that y=sin-1 x |
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Write in terms of x |
Dx(sin-1
x)=1/cos(sin-1 x)= |
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Calculations for the last line: |
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We define q
= sin-1(x). |
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Then sin(q)
= x/1. |
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Label the
triangle accordingly, with q,
x and 1. |
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Calculate the third side and label it. |
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Then cos(sin-1x)
= cos(q) = |
Or,
use a Pythagorean identity: cos(u) =
and let u = sin-1(x)
Example 4: Find the derivative of g(x) when the derivative of its inverse function f(x) is known.
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Procedure: |
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Identify the goal: Find y¢ if ... |
y=g(x) |
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Solve for x |
x=f(y) |
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Differentiate implicitly |
1=f¢(y)×y¢ |
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Solve for y¢ |
y¢=1/f¢(y) and notice from earlier that y=g(x) |
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Write in terms of x |
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ASSIGNMENT: Use this procedure to derive the formula for the derivatives of:
1. sec-1(x). Adapt the triangle procedure in example 3 for use with the secant.
2. sinh-1(x). Use these facts: (a) The derivative of sinh(x) is cosh(x); (b) cosh2(y)-sinh2(y) = 1
(In your answer, you will have
to rewrite cosh(y) as
and then as
before you can get an expression entirely in x)
Return to: Merced College; Don Power Updated 7/10/06 by Don Power